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 2-stroke minibike
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n/a
DELETED (Inactive)

9 Posts

Posted - Jan 11 2004 :  12:24:06 AM  Show Profile  Reply with Quote
cirvin was complaining about me not posting, so here i go.
i've been working on a 2-stroke minibike, (100cc)
1: 24" mountain bike using a 50t rear sprocket, 9t sprocket on a jackshaft that holds a 4" pulley (made to run 5/8" to 3/8" belts, i'm running 1/2", which gives me a 3" pulley) connected by belt to the motor, which is mounted to the bottom frame main tube by means of plate and bolt (will get a link for pictures later) so i have a form of a clutch. motor is out of a Jacobsen snow thrower, motor made by tecumseh [ has a 2" pulley on the end for 1/2" belt ] (pullstart, 4.5hp @4500rpm, i'm doing 6500rpm so i figure around 6hp), 20" rear tire. thumb throttle, hand brake, still haven't got the clutch done yet, (it'll consist of a bushed or bearing pulley and a l-bracket, foot lever). standard seat, i can't find the equation to figure out speed, if anyone can get me the equation, or figure it out (23" tire at 5000prm) i'll greatly appreciate it. thanks, and ... ... thanks.

color_orange

Aaron Cake
Administrator

Canada
6718 Posts

Posted - Jan 12 2004 :  10:22:18 AM  Show Profile  Visit Aaron Cake's Homepage  Send Aaron Cake an ICQ Message  Send Aaron Cake a Yahoo! Message  Reply with Quote
There is a ratio calculator on TZI's Scooterworld:

http://tziscooterworld.evodesign.com.au/

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BEatonNo1
Nobel Prize Winner

USA
1133 Posts

Posted - Jan 12 2004 :  11:26:24 AM  Show Profile  Visit BEatonNo1's Homepage  Reply with Quote
The circumference of the tire is the distance your going each rotation of the tire so you have to figure the distance per unit time to find your speed



Edited by - beatonno1 on Jan 12 2004 11:27:01 AM
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