| anonymous |
Fantastic Atom Expander |
Sunday, August 02, 2009 5:20:54 PM |
| J means Jumper |
| anonymous |
Fantastic Atom Expander |
Thursday, April 16, 2009 10:34:22 AM |
| What yhe J letter means? It appears like J1, J2, J3, J4, J5 and J6! Thanks! |
| Joćo Silva Brito |
Fantastic Atom Expander |
Thursday, April 16, 2009 9:59:32 AM |
| It's just me or its missing from the parts placement de led place or number 85. From my count is 97 leds not 98!?!?
Please advise! |
| Joćo Silva Brito |
Fantastic Atom Expander |
Thursday, April 16, 2009 7:02:54 AM |
| Hello! Could you please send me or improve the showned Schematic because i can't see all the numbers in the ICs. It's really important! Thank's!
|
| ChrisWhewell |
Fantastic Atom Expander |
Friday, January 23, 2009 10:38:13 AM |
| Is it a one-shot deal, or does it provide a continuous series of expanding light effect ?
Thanks |
| suraj |
Fantastic Atom Expander |
Tuesday, October 14, 2008 12:41:35 AM |
| circuit diagram is not clear |
| anonymous |
Fantastic Atom Expander |
Wednesday, April 23, 2008 12:59:36 AM |
| I built my atom expander following the design on this page. But it didn't work at first because the capacitor was to small. Eventully after trying many capacitors a 220pf(0.22uf) worked and gave me a working project. So i don't know what happend, everything else is right it was just the capacitor. oh well, anybody building the project, if it doesn't work and the ic's are working make the capacitor a bit bigger like a 220pf. |
| RedWagnum |
Fantastic Atom Expander |
Saturday, March 15, 2008 8:27:24 PM |
| This circuit works very well! I bought a couple of these in kit form from electronicsgoldmine.com a couple of years back. I substituted ultra-bright LEDs for the "100 for a buck" red ones that came with the kit. Red on the outer ring, then amber, green, blue, pink (yes PINK), and then an 8mm white in the center. Changed resistor values where needed and it works just great. I've run it from various voltage sources anywhere from 6V to 12V with no problems. The transistors get a little warm but the duty cycle is low enough that it is not an issue. |
| SeanFalloy |
Fantastic Atom Expander |
Thursday, March 13, 2008 2:17:00 PM |
| ## ali
##This circuit will never WORK! because u need to use 8 diode on out pins
the output is triggering a transistor which will amplify the signal to usable levels without the draw on the output Pins. |
| jparker |
Fantastic Atom Expander |
Thursday, December 27, 2007 8:59:46 AM |
| You cannot combine colors on the same circuit; LED's are not lamps. They are non-linear devices. Reds want to drop about 1.8 volts, yellow about 2 volts, green 2.1 (new technology green ~3.5), and blue ~3.5 volts. You can usually get by parallelling the same color on one circuit, but they won't all be the same brightness (and one might burn out). Parallelling for example a red and a green, the red gets all the current (because of its lower voltage drop). Being non-linear, the best circuit is a series resistor for each LED --- the LED will set its own voltage.
Calculate the series resistor by taking the supply voltage, subtract the LED voltage, and divide the result by the current (.010 amps for most LED's). If you use only one resistor per color, then multiply the current (.010 amps) by the number of LED's (24 for the outter ring).
Example: Blue LED
R = (Vs - Vled) / I led
R = (9 - 3.5) / (.01)(24)
R = 5.5/.24
R = 23 ohms
Be sure the resistor can handle the power:
P = (I**2)(R)
P = (.0576)(23)
P = 1.3 watts
I suggest a chip resistor for EACH Light Emitting Diode. LES's will be safer, resistors cooler, and the world geopolitically safer (maybe not the last one)... (Editor's notes: Just a note that the version I made with a rainbow of different LEDs has been working fine for over 10 years.) |