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This inverter circuit can provide up to 800mA of 12V power from a 6V supply. For example, you could run 12V car accessories in a 6V (British?) car. The circuit is simple, about 75% efficient and quite useful. By changing just a few components, you can also modify it for different voltages. |
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How can i do a converter from 10V to 12V?
Best Regards! (Editor's notes: The same way as this one is built.) |
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| i have a 20 amp transformed and rectified 24v supply and would like a basic schematic to covert to regulated high current 15v dc and have plenty of 2n3055 transistors handy.thanks | ||
| NICE! it won't be very efficient, but it WILL be fun! Use a filter on the output and input and put in a shielded box... | ||
| HOW TO CONVERT DC 6V-DC24 VOLT, PLEASE E MAIL THE CIRCUIT DIAGRAM AND COMPONENT PROPERTIES | ||
| i understand this concept & i like it. | ||
| I am a beginner in this field and have visited this website for the first time and have found it excellent,you are doing just a marvallous job. | ||
| what is 40mm, the ring diameter or the whole inductor diameter?, what would happen if i use a smaller or larger inductor? | ||
| ok...I have a question, I have a specific project that I need to make a HV (100-120Vdc) from a120vac -500 watt power supply. I can get the 100vdc threw a full wave bridge rectifier...but not stable at all. I need extramely low amps...no more than 3, but would like to maintain 100-120VDC out for motor use. Can anyone help me here? Send me an email directly...Thanks | ||
| I'm beginning learner. Please show me how to do 24V to 12V Converter and 12V to 15V Converter. Thank you so much. | ||
| Aleksander, Wook is right. You can't build that circuit. Even if you did change out the inductor it would be impossible. 10Vdc * 20mA =0.2Watts for the input. 12Vdc * 0.36A = 4.32 Watts. for output. Output power cannot be greater than input power. An input of 10Vdc converter at 20mA outputting 12Vdc can output at the very most, 16.7mA. And that is with 100% efficiency. Realistically you can output maybe 13mA. Also, this circuit is not called an inverter. Inverters take a DC voltage and convert it to AC, so I don't know why it is named inverter. The correct name would be a Boost DC Converter. | ||
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