| Brian Nebeker |
Automatic Load Sensing Power Switch |
Thursday, November 17, 2011 12:21:11 PM |
| Current sensing using a large resistor is wasteful of power and sensing power on the neutral side can cause dangerous conditions. If R1 fails it will leave the load side of the neutral line at the potential of the hot line.
A far safer way of sensing current is to use a hall effort sensor such as those provided by Allegro. These sensors provide high voltage isolation and high power level handling due to the fact that they use a magnetic field instead of a resistance to sense the current. I have used these sensors on several projects and they make life much easier.
If there is enough interest I could post of example of this circuit using a hall effect sensor. |
| anonymous |
Automatic Load Sensing Power Switch |
Monday, April 25, 2011 9:43:10 PM |
| anybody has got this working?? |
| PsyPhi |
Automatic Load Sensing Power Switch |
Wednesday, November 04, 2009 12:42:46 AM |
| There's nothing in this circuit to keep the voltage across C3 from rising above its rated voltage when Q1 is off (i.e. when no current is being drawn by the master load). The capacitor will try to charge up to about 170V (the peak voltage of 120 VAC RMS), but it will eventually fail (and might literally explode!) once the voltage gets significantly above the nominal 35V. A zener or even a resistor in parallel with C3 could solve this problem. |
| Abdul Wahid |
Automatic Load Sensing Power Switch |
Sunday, March 01, 2009 5:42:16 AM |
| The values for 240VAC operation are R2 = 50K, 1W and R6 = 200K, 1W. these are calculated just using Ohms law by keeping the current at same level. if you want to increase the current then increase the wattage with same ratio, i.e doubling current will double the wattage of R2 and R6 |
| anonymous |
Automatic Load Sensing Power Switch |
Sunday, February 15, 2009 3:42:05 PM |
| Not sure this will work. To keep a 12V relay energised would need something like 50mA. So the power dissipated in R6 would be 0.050 * 0.050 * 4700 = 11.75W! |
| Eliud kabuga Gichaiya |
Automatic Load Sensing Power Switch |
Wednesday, September 24, 2008 6:58:46 AM |
| 1. the value of r2 r6 need to be changed if you are in 240v .what is the value of this resistors.
2. if u need islorate .that is high version, about 15amp.what is rate of resistor. |
| Loupitou |
Automatic Load Sensing |
Thursday, June 05, 2008 12:40:02 AM |
| To make a "high power version" capable of sustaining ~15A total (Master + slave peak ), I understand that I need to change the W rating of R1 and also the relay/switch model but anything else ? |
| gagan kapoor |
Automatic Load Sensing Power Switch |
Monday, May 26, 2008 2:40:53 AM |
| what should be the value of r2 & r6 when connected to 240vac |
| scofield |
Automatic Load Sensing Power Switch |
Monday, February 18, 2008 11:40:55 PM |
| what is the value of R2 and R6, when we want to use 240v as the supply???urgent... |
| anonymous |
Automatic Load Sensing Power Switch |
Thursday, February 14, 2008 11:10:27 PM |
| ohms law , would indicate half the resistance , not double and it would be 4 times the wattage(power dissapation---...---...---...G.R.. . . . . |